Take out a marble.
There are seven black marbles and nine white marbles.
Call it the second marble.
9 blue marbles 8 green marbles 4 red marbles 8 white marbles and 6 yellow marbles.
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What is the approximate probability of drawing two black marbles and then.
So let s draw this bag here.
Note that there are 16 total marbles.
The probability of drawing to marbles then a white one without replacement will be as follows.
Let s do a couple of exercises from our probability one module.
So that s my bag and we re going to assume that it s a transparent bag so it looks like a.
You draw ten marbles out as before and this time you get seven black and three white.
All of the original white marbles are still in the bag so there is a 4 out of 17 or 4 17 chance that the next marble taken out of the bag will be white.
What is the probability of randomly selecting a non blue marble from of the bag.
P r r 9 20 9 20 81 400 2025.
There are a number of ways of approaching this problem but the easiest solution is to realize that it doesn t matter what order you took the marbles out in.
On the first you have 10 16 chances to draw a red.
There are 35 marbles in a bag.
A bag contains five yellow marbles nine red marbles three blue marbles six white marbles and seven black marbles.
Write the probability as a fraction in simplest form a decimal and a percent.
Trivially then the answer is frac 1 3 since there is one white.
So we have a bag with 9 red marbles 2 blue marbles and 3 green marbles in it.
There are 18 marbles in total.
This is our denominator.
Therefore the probability of a is 10 16 9 15 0 375.
A is simply a set of sequential events.
This second urn also contains 100 marbles that are either black or white but you do not know their breakdown.
There are seven black marbles and nine white marbles in a bag.
One of them is removed so now there are 17 marbles.
There could be anywhere between zero and 100 black marbles and the appropriate number of white marbles to make up the balance.