Let the velocity of the revolving satellite be v.
Time period of a satellite of mass m revolving around very close to earth.
The period of a satellite is the time it takes it to make one full orbit around an object.
The speed of the satellite is 7 519 km s and the period of revolution of the satellite is 5930 s.
Centripetal acceleration v r.
Let v 0 be the orbital velocity of the satellite.
If you know the satellite s speed and the radius at which it orbits you can figure out its period.
T 5071 3600 1 408 h.
Acceleration due to earth at a point near to earth g g m r.
If the density of moon is d the time period of revolution of an artificial satellite in a circular orbit very close to the surface of the moon is.
The mean angular velocity of the earth around the sun is 1 per day.
A satellite of mass is orbiting the earth in a cicular orbit of radius it starts losing its mechanical energy due to small air resistance at the rate of joule sec.
The time period of a satellite orbiting around the earth is given by.
Let the mass of earth be m.
Distance of moon from the earth 3 84 x 10 5 km.
View answer a satellite close to the earth is in orbit above the equator with a period of revolution of 1.
The period of the earth as it travels around the sun is one year.
Suppose a satellite of mass m revolving around the earth at height h form the surface as shown in the figure.
The speed of the satellite in its orbit is.
The time taken by the satellite to hit the suface of the earth is and are the mass and radius of the earth.
A satellite of mass m is revolving close to the surface of a planet of density d with time period t what is the value of universal gravitational constant 6537268.
Consider a satellite of mass m moving in a circular orbit around the earth at a distance r from the centre of the earth.
The speed of the satellite is 7 931 km s and the time of revolution of the satellite is 1 408 h.
From the following data calculate the period of revolution of the moon around the earth.
T 2πr v c 2 x 3 142 x 6400 7 931 5071 s.
For synchronisation its period of revolution around the earth must be equal to the period of rotation of the earth ie 1 day 24 hr 86400 seconds.
As the movement of satellites is uniform circular motion so there will be only centripetal acceleration.
5 h o u r s in the same sense as that of the earth.
Radius of earth r 6400 km 6 4 x 10 8 m radius of orbit of moon r 3 84 x 10 5.
This velocity is called the orbital velocity of the satellite.
A satellite keeps on revolving round the earth with a certain velocity which depends on the radius of its orbit.
Let the radius of earth be r.